Physics - Elasticity Question with Solution | TestHub

PhysicsElasticityMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

The Young's modulus of the material of wire is $2 \times 10^{10} {N m}^{- 2} .$ If the elongation strain is $1%$ , then the energy stored in the wire per unit volume in ${J m}^{- 3}$ is

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Answer:

Solution:

Per unit volume energy stored

$= \frac{1}{2} \times Y \times {(strain)}^{2} = \frac{1}{2} \times Y \times {(\frac{l}{L})}^{2}$

given $l = L \times 1 %$

or $l = \frac{L}{100}$

Thus per unit volume energy stored $= \frac{1}{2} \times 2 \times 10^{10} \times {(\frac{L}{100 L})}^{2}$

$= 10^{6} {J m}^{- 3}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:ElasticitySubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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