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Physics - Elasticity Question with Solution | TestHub

PhysicsElasticityMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

Two metal wires $P$ and $Q$ of same length and material are stretched by the same load. Their masses are in the ratio $m_{1} : m_{2}$ . The ratio of elongations of wire is

Options:

Answer:

Solution:

$m_{1} : m_{2}$

$Y = \frac{F l}{A Δ l}$

$Δ l = \frac{F l}{Y A}$

$m = ρ V = ρ \times A \times l$

$A α m$

$\frac{Δ l_{1}}{Δ l_{2}} = \frac{A_{2}}{A_{1}} = \frac{m_{2}}{m_{1}}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:ElasticitySubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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