Physics - Elasticity Question with Solution | TestHub

Given,

Bulk modulus of water$B=2100 \mathrm{M}\mathrm{P}\mathrm{a}$

$=2100\times {10}^6\mathrm{ }\mathrm{P}\mathrm{a}$

We know that,

$\mathrm{\Delta }P=B\left(\frac{-\mathrm{\Delta }V}{V}\right)$

Here,$\frac{∆V}{V}\times 100$

$\frac{∆V}{V}=\frac{0.004}{100}$

$\Delta P=2100\times {10}^6\times \left(\frac{0.004}{100}\right)$

$=\frac{2100\times {10}^6\times 4}{1000\times 100}$

$=\frac{8400\times {10}^6}{{10}^5}$

$=84000 \mathrm{P}\mathrm{a}$

$=84 \mathrm{k}\mathrm{P}\mathrm{a}$