Let a steel bar of length l , breadth b and depth d be loaded at the center by a load W . Then the sag of bending of beam is (Y = Young's modulus of steel)

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TestHub · Accepted Answer

The sag of bending of beam is given by.

$δ = \frac{W l^{3}}{48 Y I}$ Where W is load, L is length, Y is young's modulus and $I i s \frac{b d^{3}}{12}$ (area moment of inertia)

$∴ δ = \frac{W l^{3}}{48 Y} \times \frac{12}{b d^{3}} = \frac{W l^{3}}{4 b d^{3} Y}$

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