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Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityElectrical instrumentEasy2 minQB

PhysicsEasynumerical

Four resistances of $15Ω, 12Ω, 4Ω$ and $10Ω$ respectively in cyclic order to form Wheatstone’s network. The resistance that is to be connected in parallel with the resistance of $10Ω$ to balance the network is ______________ $Ω.$

Answer:

10.00

Solution:

$\frac{10 R}{10 + R} \times 12 = 15 \times 4$ On solving

$R = 10Ω$

Stream:JEESubject:PhysicsTopic:Current ElectricitySubtopic:Electrical instrument

⏱ 2mℹ️ Source: QB

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