Physics - Current Electricity Question with Solution | TestHub

$R=3\Omega +2\Omega$. Let potential at $P=0$, $\therefore V_A=6\mathrm{V},V_D=-9\mathrm{V}$, and$VQ=x$. Apply K.C.L. at $x$, $\frac{x-6}{3}+\frac{x-0}{1}+\frac{x+9}{5}=0$. Solving, $x=\frac{3}{23}\mathrm{V}$. So, current in $1\Omega$ $\Rightarrow i=\frac{\frac{3}{23}-0}{1}$ from $Q$ to $P$ $\Rightarrow i=0.13\text{A}$ from $Q$ to $P$