In the given figure R 1 = 10Ω , R 2 = 8Ω , R 3 = 4Ω and R 4 = 8Ω . Battery is ideal with emf 12 V . Equivalent resistant of the circuit and current supplied by battery are respectively :

Question

In the given figure R 1 ​ = 10Ω , R 2 ​ = 8Ω , R 3 ​ = 4Ω and R 4 ​ = 8Ω . Battery is ideal with emf 12 V . Equivalent resistant of the circuit and current supplied by battery are respectively :

TestHub · Accepted Answer

Here R 2 ​ , R 3 ​ , R 4 ​ are in parallel ​ R 234 ​ 1 ​ = R 2 ​ 1 ​ + R 3 ​ 1 ​ + R 4 ​ 1 ​ R 234 ​ = 2Ω ​ ​ R 234 ​ is in series with R 1 ​ so ​ R eq ​ = R 234 ​ + R 1 ​ = 2 + 10 = 12Ω i = 12 12 ​ = 1 Amp ​ ​

Physics - Current Electricity Question with Solution | TestHub

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