Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityCircuit AnalysisEasy2 minQB

PhysicsEasysingle choice

In the given circuit, the current in resistance $R_{3}$ is:

Answer:

Solution:

Equivalent resistance, $R_{e q} = 2Ω + \frac{4 \times 4}{4 + 4} Ω + 1Ω = 5Ω$

Current through battery, $i = \frac{V}{R _{e q}} = \frac{10}{5} = 2 A$

Current in resistance $R_{3} = 2 \times (\frac{4}{4 + 4})$

$= 2 \times \frac{4}{8}$

$= 1 A$

Stream:JEESubject:PhysicsTopic:Current ElectricitySubtopic:Circuit Analysis

⏱ 2mℹ️ Source: QB

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