A network consisting of three resistors, three cells and a capacitor is shown in figure. At steady state
List - I
List - II
(P) Current in branch EB is
(1) $10 μ C$
(Q) Current in branch CB is
(2) 0.5 A
(R) Current in branch ED is
(3) 1.5 A
(S) Charge on capacitor is
(4) $5 μ C$

(5) None of these

Question

A network consisting of three resistors, three cells and a capacitor is shown in figure. At steady state

List - I	List - II
(P) Current in branch EB is	(1) $10 μ C$
(Q) Current in branch CB is	(2) 0.5 A
(R) Current in branch ED is	(3) 1.5 A
(S) Charge on capacitor is	(4) $5 μ C$
	(5) None of these

TestHub · Accepted Answer

At steady state the capacitor branch carries no current; solving the resistor-cell network gives branch currents 2 A, 1.5 A and 0.5 A as marked. Charge on capacitor: q = 5 [ 10 − 8 ] = 10 μ C

Physics - Current Electricity Question with Solution | TestHub

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