Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityElectrical instrumentEasy2 minQB
PhysicsEasysingle choice

A voltmeter of variable ranges3 V, 15 V, 150 Vis to be designed by connecting resistancesR1, R2, R3in series with a galvanometer of resistanceG = 20 Ω, as shown in the figure. The galvanometer gives full pass through its coil. Then, the resistancesR1, R2andR3(in kilo ohms) should be, respectively

Options:

Answer:
B
Solution:

R =VIg – Rg

R1 =3Ig– Rg = 2980 Ω = 2.98 kΩ

R1 + R2=15Ig– Rg = 14980Ω = 14.98 kΩ

R1 + R2 + R3= 150Ig – Rg = 149980 Ω

= 149.98 kΩ

⇒R1 = 2.98 kΩ

R2 = 14.98 – 2.98 = 12 kΩ

R3 = 149.98 – 14.98 = 135 kΩ

Stream:JEESubject:PhysicsTopic:Current ElectricitySubtopic:Electrical instrument
⏱ 2mℹ️ Source: QB

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