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Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityElectrical PowerMedium2 minQB

PhysicsMediumsingle choice

A current of $2 mA$ was passed through an unknown resistor which dissipated a power of $4.4 W .$ Dissipated power when an ideal power supply of $11 V$ is connected across it is:

Options:

Answer:

Solution:

$P = \frac{V ^{2}}{R} = i^{2} R R e s i s t an ce R = \frac{V ^{2}}{P} = \frac{P}{i ^{2}}$
Here, Power $P = 4.4 W an d i = 2 mA$

so $R = \frac{4.4}{4 \times 1 0 ^{- 6}}$ $Ω$

When $11 V$ power supply is connected across R

$P^{'} = \frac{1 1 ^{2}}{4.4} \times 4 \times 1 0^{- 6}$

$= 11 \times 1 0^{- 5} W$ .

Stream:JEESubject:PhysicsTopic:Current ElectricitySubtopic:Electrical Power

⏱ 2mℹ️ Source: QB

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