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Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityBatteryMedium2 minQB

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A $5 V$ battery with internal resistance $2Ω$ and a $2 V$ battery with internal resistance $1Ω$ are connected to a $10Ω$ resistor as shown in the figure. The current in the $10Ω$ resistor is

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Solution:

$V_{P_{2}} - V_{P_{1}} = \frac{\frac{5}{2} + \frac{0}{10} - \frac{2}{1}}{\frac{1}{2} + \frac{1}{10} + \frac{1}{1}} I = \frac{V _{P_{2}} - V _{P_{1}}}{10} = 0.03 from P_{2} \to P_{1}$

Stream:JEESubject:PhysicsTopic:Current ElectricitySubtopic:Battery

⏱ 2mℹ️ Source: QB

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