In a building there are 15 bulbs of 45 W , 15 bulbs of 100 W , 15 small fans of 10 W and 2 heaters of 1 k W . The voltage of electric main supply is 220 V . The minimum fuse capacity (rated value) of

Question

In a building there are 15 bulbs of 45 W , 15 bulbs of 100 W , 15 small fans of 10 W and 2 heaters of 1 k W . The voltage of electric main supply is 220 V . The minimum fuse capacity (rated value) of the building will be:

TestHub · Accepted Answer

Total power is ( 15 × 45 ) + ( 15 × 100 ) + ( 15 × 10 ) + ( 2 × 1000 ) = 4325 W So current = 220 4325 ​ = 19.66 A ≈ 20 A so we have to use a fuse which can tolerate atleast 20 A current.

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