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Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityCircuit AnalysisHard2 minQB

PhysicsHardnumerical

In the given figure, the value of $V_{0}$ will be _____ $V$ .

Answer:

4.00

Solution:

Using Kirchhoff's junction rule,
$\frac{V _{0} - 2}{1 k Ω} + \frac{V _{0} - 4}{1 k Ω} + \frac{V _{0} - 6}{1 k Ω} = 0$
$3 V_{0} - 12 = 0$
$V_{0} = 4 V$

Stream:JEESubject:PhysicsTopic:Current ElectricitySubtopic:Circuit Analysis

⏱ 2mℹ️ Source: QB

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