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PhysicsCurrent ElectricityElectrical PowerEasy2 minQB

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Ratio of thermal energy released in two resistor $R$ and $3 R$ connected in parallel in an electric circuit is :

Answer:

Solution:

In parallel connection, potential difference across resistors remains the same.

Thermal energy released in resistor is given by $H = \frac{V ^{2}}{R} \times t$

So, the ratio is $\frac{H _{1}}{H _{2}} = \frac{\frac{V ^{2} t}{R}}{\frac{V ^{2} t}{3 R}} = \frac{3 R}{R} = 3 : 1$ .

Stream:JEESubject:PhysicsTopic:Current ElectricitySubtopic:Electrical Power

⏱ 2mℹ️ Source: QB

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