Current measured by the ammeter ( A ) in the reported circuit when no current flows through 10Ω resistance, will be _____ A .

Question

TestHub · Accepted Answer

This is a Wheatstone circuit. For the current to be zero in $10Ω$ the Wheatstone circuit should be balanced. Therefore,

$\frac{R}{3} = \frac{4}{6} \Rightarrow R = 2Ω$

Now, the equivalent resistance across the battery will be,

$R_{e q} = \frac{( 2 + 4 ) \times ( 3 + 6 )}{( 2 + 4 ) + ( 3 + 6 )} = 3.6Ω$

Therefore, the current measured by the ammeter is $i = \frac{V}{R} = \frac{36}{3.6} = 10 A$ .

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