Physics - Current Electricity Question with Solution | TestHub

In the given circuit,$\mathrm{B}$and$\mathrm{E}$are at the same potential. Points$\mathrm{C}$and$\mathrm{F}$are also at the same potential.

Therefore, the resistance between$\mathrm{B}$and$\mathrm{E},\mathrm{ }\mathrm{C}$and$\mathrm{F}$will be ineffective and neglected. Now, the circuit becomes



In the above circuit, branch$\mathrm{ABCD}$and$\mathrm{AEFD}$are in the parallel combination.

Thus, the net resistance of the circuit.

$\frac{1}{R_{\mathrm{n}\mathrm{e}\mathrm{t}}}=\frac{1}{5+5+5}+\frac{1}{5+5+5}=\frac{1}{15}+\frac{1}{15}=\frac{2}{15}$

$\Rightarrow R_{\mathrm{n}\mathrm{e}\mathrm{t}}=\frac{15}{2} \mathrm{\Omega }$

$\therefore$Current,$I=\frac{V}{R_{\mathrm{n}\mathrm{e}\mathrm{t}}}=\frac{10}{15/2}=\frac{20}{15}=\frac{4}{3}=1.33 \mathrm{A}$