Physics - Current Electricity Question with Solution | TestHub

Using KVL :

$100\left(\text{i}+\text{0.05}\right)+50\text{i}-2=0$

$150\text{i}+3=0$

$\text{i}=\frac{-3}{150}=-\text{0.02}A$

$=-20mA$

So, the direction of i is opposite to what we have assumed. If we redraw the circuit.



Using KVL :

$20\times \text{0.05}+100\times \text{0.03}-{\text{V}}_2=0$

$1+3-{\text{V}}_2=0$

${\text{V}}_2=4\text{V}$