The resistance of a conductor at 1 5 ∘ C is 16Ω and at 10 0 ∘ C is 20Ω. What will be the temperature coefficient of resistance of the conductor?

16 = R 0 [ 1 + α ( 15 − T o ) ] 20 = R 0 [ 1 + α ( 100 − T 0 ) ] Assuming T o = 0 ∘ C , as a general convention. ⇒ 20 16 = 1 + α × 100 1 + α × 15 ⇒ α = 0.003 ( _ ∘ C ) − 1

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Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityMicroscopicEasy2 minQB

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The resistance of a conductor at $1 5^{\circ} C$ is $16Ω$ and at $10 0^{\circ} C$ is $20Ω.$ What will be the temperature coefficient of resistance of the conductor?

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Solution:

$16 = R_{0} [1 + α (15 - T_{o})]$

$20 = R_{0} [1 + α (100 - T_{0})]$

Assuming $T_{o} = 0^{\circ} C$ , as a general convention.

$\Rightarrow \frac{16}{20} = \frac{1 + α \times 15}{1 + α \times 100}$

$\Rightarrow α = 0.003 (_^{\circ} C)^{- 1}$

Stream:JEESubject:PhysicsTopic:Current ElectricitySubtopic:Microscopic

⏱ 2mℹ️ Source: QB

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