Physics - Current Electricity Question with Solution | TestHub

Using kirchhoff's law in the circuit $A\mathrm{C}DB$, we get

Voltage at $B$= voltage at $A$ + voltage of battery of $1\mathrm{V}$ + potential difference across $2\Omega$ resistance - voltage of battery of $2\mathrm{V}$

$\Rightarrow V_A+1+2(1)-2=V_B$

Now potential at point $B$ with respect to point $A$ is given by,

$\Rightarrow V_B-V_A=1\mathrm{V}$