In the given circuit diagram, the currents, $I_{1} = - 0.3 A, I_{4} = 0.8 A$ and $I_{5} = 0.4 A,$ are flowing as shown. The currents $I_{2}, I_{3}$ and $I_{6},$ respectively, are:

Question

In the given circuit diagram, the currents, I 1 ​ = − 0.3 A , I 4 ​ = 0.8 A and I 5 ​ = 0.4 A , are flowing as shown. The currents I 2 ​ , I 3 ​ and I 6 ​ , respectively, are:

TestHub · Accepted Answer

G i v e n I 1 ​ = − 0.3 A , I 4 ​ = 0.8 A , I 5 ​ = 0.4 A , in s er i e s co nn ec t i o n c u rre n tw i ll b e s am e , h e n ce I 5 ​ = I 6 ​ = 0.4 A , A ccor d in g t o ki rc h o f f ′ s j u n c i o n r u l e , a l g e b r ai c s u m o f t h ec u rre n t s m ee t in g a ttt h e j u c t i o ni s z ero . i . ec u rre n t s f l o w in g in t o t h e j u n c t i o ni s t ak e na s p o s i t i v e an d c u rre n t f l o w in g o u t o f t h e j u n c t i o ni s t ak e na s n e g a t i v e . A tt h e j u n c t i o n R , − I 4 ​ + I 2 ​ + I 1 ​ = 0 ⇒ − 0.8 + I 2 ​ − 0.3 = 0 ⇒ I 2 ​ = 1.1 A At j u n c t i o n Q , I 6 ​ + I 3 ​ − I 2 ​ − I 1 ​ = 0 ⇒ 0.4 + I 3 ​ − 1.1 + 0.3 = 0 ⇒ I 3 ​ = 1.1 − 0.7 = 0.4 A It is problem of kirchhof's current law. I 6 ​ = 0.4 A I 3 ​ = 0.8 A − O .4 A = 0.4 A I 2 ​ = ( 0.8 + 0.3 ) A = 1.1 A

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