Start Free Mock LoginAlready registered? Login here

Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityElectrical instrumentEasy2 minQB

PhysicsEasysingle choice

In an experiment according to set up, when $E_{1} = 12 V$ and internal resistance zero, $e = 2 V$ . The galvanometer reads zero, then $X$ would be-

Options:

Answer:

Solution:

Voltage across $X$ is $2 v$

So $(\frac{E_{1}}{500 + X}) X = 2$

$\Rightarrow (\frac{12}{500 + X}) X = 2$

$\Rightarrow 12 X = 1000 + 2 X$

$\Rightarrow 10 X = 1000$

$X = 100 Ω$

Stream:JEESubject:PhysicsTopic:Current ElectricitySubtopic:Electrical instrument

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...