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Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityElectrical instrumentEasy2 minQB

PhysicsEasysingle choice

The ammeter reading in the given circuit is

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Answer:

Solution:

$E_{e q} = \frac{3 \times 1 + 6 \times 2}{1 + 2} = 5 V, r_{e q} = \frac{2 \times 1}{2 + 1} = \frac{2}{3} Ω$

$I = \frac{5}{10 + 2 / 3} = \frac{15}{32} A$

Stream:JEESubject:PhysicsTopic:Current ElectricitySubtopic:Electrical instrument

⏱ 2mℹ️ Source: QB

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