Physics - Current Electricity Question with Solution | TestHub

$$\begin{array}{rl}& {\mathrm{R}}_1=\mathrm{P}+\mathrm{Q}=2\Omega +4\Omega =6\Omega \\ & {\mathrm{R}}_2=\mathrm{R}+\mathrm{S}=1\Omega +2\Omega =3\Omega \\ & {\mathrm{I}}_1{\mathrm{R}}_1={\mathrm{I}}_2{\mathrm{R}}_2\\ & {\mathrm{I}}_1=\frac{{\mathrm{R}}_2}{{\mathrm{R}}_1}{\mathrm{I}}_2=\frac{3}{6}{\mathrm{I}}_2=\frac{{\mathrm{I}}_2}{2}\end{array}$$ or ${\mathrm{I}}_2=2{\mathrm{I}}_1$ Heat flow $\mathrm{H}={\mathrm{I}}^2\mathrm{Rt}$ For $\mathrm{Q},{\mathrm{H}}_{\mathrm{Q}}={\mathrm{I}}_1^2\mathrm{Qt}=\frac{{\mathrm{I}}_2^2}{4}\times 4\mathrm{t}={\mathrm{I}}_2^2\mathrm{t}$ For $\mathrm{S},{\mathrm{H}}_{\mathrm{S}}={\mathrm{I}}_2^2\mathrm{St}={\mathrm{I}}_2^2\cdot 2\mathrm{t}=2{\mathrm{I}}_2^2\mathrm{t}$ $\therefore$ Greatest amount of heat generated by $\mathrm{S}$.