Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityCircuit AnalysisHard2 minQB

PhysicsHardsingle choice

In the figure shown, the current in the $10 V$ battery is close to :

Answer:

Solution:

$- 5 i_{2} - 10 (i_{1} + i_{2}) - 2 i_{2} + 20 = 0$

$- 10 i_{1} - 17 i_{2} + 20 = 0$

$- 10 + 4 i_{1} + 10 (i_{1} + i_{2}) = 0$

$14 i_{1} + 10 i_{2} + 10 = 0$

$10 i_{1} + 17 i_{2} = 20 \to \times 10$

$14 i_{1} + 10 i_{2} = 10 \to 17$

$- 138 i_{1} = 30$

$i_{1} = - \frac{30}{138} = - 0.217$

$i_{1}$ is negative it means current flows from positive to negative terminal

Stream:JEESubject:PhysicsTopic:Current ElectricitySubtopic:Circuit Analysis

⏱ 2mℹ️ Source: QB

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