Physics - Current Electricity Question with Solution | TestHub

Given $G=100\Omega$, $I_g=1\text{ mA}=10^{-3}\text{ A}$, and $I=10\text{ A}$.

The shunt resistance $S$ required to convert a galvanometer into an ammeter is given by:

$S=\frac{I_{g}G}{I-I_g}$

Substituting the values:

$S=\frac{10^{-3}\times 100}{10-10^{-3}}$

Since $10\gg 10^{-3}$, we can approximate $10-10^{-3}\approx 10$.

$S\approx \frac{0.1}{10}=0.01\Omega$

Answer: $0.01\Omega$