Physics - Current Electricity Question with Solution | TestHub

The maximum voltage that the voltmeter can measure is given by

$V=I_g(G+R)$

Substituting the given values:

$V=10\times 10^{-3}\times (80+920)$

$V=10\times 10^{-3}\times 1000=10\text{ V}$

The least count of the voltmeter is the voltage measured by one division on the scale.

$\text{Least count}=\frac{V}{N}$

where $N$ is the number of divisions on the scale.

$0.2=\frac{10}{N}$

$N=\frac{10}{0.2}=50$

The number of divisions on the scale is 50.

Answer: 50