Physics - Current Electricity Question with Solution | TestHub

The given circuit consists of two batteries and a resistor connected in a single loop.

Let us determine the net electromotive force (EMF) in the circuit. The two batteries are connected such that their positive terminals face each other (or negative terminals face each other), which means they oppose each other.
The top battery has an EMF of $E_1=5\text{ V}$.
The bottom battery has an EMF of $E_2=100\text{ V}$.

Since they are in opposition, the net EMF ($E_{\text{net}}$) is the difference between their voltages:
$E_{\text{net}}=E_2-E_1$
$E_{\text{net}}=100\text{ V}-5\text{ V}=95\text{ V}$

The total resistance in the circuit is given by the single resistor:
$R=19\Omega$

Using Ohm's law, the current $I$ flowing through the circuit is:
$I=\frac{E_{\text{net}}}{R}$
$I=\frac{95}{19}$
$I=5\text{ A}$

Answer: 5 A