The number of electrons flowing per second in the filament of a 110 W bulb operating at 220 V is : ( Given e = 1.6 × 1 0 − 19 C )

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Power ( P ) = V . I ​ ⇒ 110 = ( 220 ) ( I ) ⇒ I = 0.5 A ​ Now, I = t n ⋅ e ​ ​ ⇒ 0.5 = ( t n ​ ) ( 1.6 × 1 0 − 19 ) ⇒ t n ​ = 1.6 × 1 0 − 19 0.5 ​ ⇒ t n ​ = 31.25 × 1 0 17 ​

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