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Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityMicroscopicMedium2 minPYQ_2023

PhysicsMediumsingle choice

An electron of mass ' $m$ ' and charge ' $q$ ' is accelerated from rest in a uniform electric field of strength ' $E$ '. The velocity acquired by the electron, when it travels a distance ' $L$ ', is

Options:

Answer:

Solution:

We know $F = ma$ and $F = qE$ $\Rightarrow qE = ma$ $∴ \frac{qE}{m} = a$ According to equation of motion, $∴ v^{2} - u^{2} = 2 a L v^{2} - 0^{2} = 2 a L v^{2} = 2 a L v = 2 a L v = \frac{2 qE L}{m}$

Stream:MHT_CETSubject:PhysicsTopic:Current ElectricitySubtopic:Microscopic

⏱ 2mℹ️ Source: PYQ_2023

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