Physics - Current Electricity Question with Solution | TestHub

Given: Resistance of the galvanometer $=\mathrm{G}$ Range of the galvanometer $={\mathrm{V}}_{\mathrm{g}}$ The series resistance value to be used for converting the galvanometer into a voltmeter of range 0 to ${\mathrm{V}}_{{\mathrm{g}}^{\prime }}$ is, $\mathrm{R}=\frac{{\mathrm{V}}_{\mathrm{z}}}{{\mathrm{I}}_{\mathrm{g}}}-\mathrm{G}$ Also, ${\mathrm{I}}_{\mathrm{g}}=\frac{{\mathrm{V}}_{\mathrm{g}}}{\mathrm{G}}$ To increase the measuring range to $\mathrm{V}$, the new resistance value ${\mathrm{R}}^{\prime }=\frac{\mathrm{V}}{\left(\frac{{\mathrm{V}}_{\mathrm{g}}}{\mathrm{G}}\right)}-\mathrm{G}$ $=\frac{\mathrm{VG}}{{\mathrm{V}}_{\mathrm{s}}}-\mathrm{G}=\mathrm{G}\left(\frac{\mathrm{V}}{{\mathrm{V}}_{\mathrm{g}}}-1\right)$