Physics - Current Electricity Question with Solution | TestHub

Let net resistance of the given infinite network be ' $R$ ' Now, the circuit can be modified asNow, $R_{\text{net }}=R=1+1+\frac{R}{R+1}$ $\begin{array}{rl}& \therefore R=2+\frac{R}{R+1}\\ & R^2+R=2R+2+R\\ & R^2-2R-2=0\\ & R=\left(\frac{2\pm \sqrt{4+8}}{2}\right)\\ & R=(1+\sqrt{3})\Omega \end{array}$