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PhysicsCurrent ElectricityMicroscopicEasy2 minPYQ_2021
PhysicsEasysingle choice

A current of5 Ais passing through a non-linear magnesium wire of cross-section0.04 m2. At every point the direction of current density is at an angle of60°with the unit vector of area of cross-section.
The magnitude of electric field at every point of the conductor is: (resistivity of magnesiumρ=44×10-8 Ωm)

Options:

Answer:
C
Solution:

I=J·A=JAcos(θ)
5=J4100×cos(60)
J=5×50=250 A m-2
Now,E=ρ×J
=44×10-8×250=11×10-5 V m-1

Stream:JEESubject:PhysicsTopic:Current ElectricitySubtopic:Microscopic
2mℹ️ Source: PYQ_2021

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