Physics - Current Electricity Question with Solution | TestHub

In the given circuit diagram,$\mathrm{3 }\mathrm{\Omega }$and$\mathrm{3 }\mathrm{\Omega }$are in series

$3+3=\mathrm{6 }\mathrm{\Omega }$

$\mathrm{6 }\mathrm{\Omega }$and$\mathrm{6 }\mathrm{\Omega }$are in parallel

$\frac{6\times 6}{6+6}=\mathrm{3 }\mathrm{\Omega }$

This$\mathrm{3 }\mathrm{\Omega }$is in series with$\mathrm{4 }\mathrm{\Omega }$and 5$\mathrm{\Omega }$

$4+3+5=\mathrm{12 }\mathrm{\Omega }$