Physics - Current Electricity Question with Solution | TestHub

From the symmetry current in$\text{AO}$will be same as current in$\text{OB}$

Simiarly current$\text{CO}$equal to current in$\text{OD}$

The given circuit can be redrawn as



$\frac{1}{R_{AB}}=\frac{1}{\frac{40}{3}}+\frac{1}{10}+\frac{1}{5}$

$\therefore R_{\text{AB}}=\frac{8}{3}\mathrm{ \Omega }$