Physics - Current Electricity Question with Solution | TestHub

Number of electrons$n_e=3.13\times {10}^{15}$

Number of protons$n_p=3.12\times {10}^{15}$

Now, the current is given by the relation

$i=n_e{q}_e+n_p{q}_p$

$=3.13\times {10}^{15}\times 1.6\times {10}^{-19}+3.12\times {10}^{15}\times 1.6\times {10}^{-19}$

$=1\times {10}^{-3}=1\mathrm{ }\mathrm{mA}$

Now, due to excess the charge on electrons, the direction of the current will be towards right.