Physics - Current Electricity Question with Solution | TestHub

As voltage across the resistors$R_2 \mathrm{a}\mathrm{n}\mathrm{d} R_3$is same and they show same dissipation of energy, so using the relation for energy,$H=\frac{V^2}{R}t, \mathrm{w}\mathrm{e}\mathrm{ }\mathrm{h}\mathrm{a}\mathrm{v}\mathrm{e} R_2=R_3$. Thus, the current in each resistor

$ie,I_1=I$/2 and$I_2=I$/2




Since the energy dissipation is same in all the three resistors, so

${ I}^2{R}_{1}t=I_1^2{R}_{2}t$

or$I^2{R}_{1}t={\left(I/2\right)}^2{R}_{2}t$

or$R_1=R_2$/4