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Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityBatteryEasy2 minPYQ_2020

PhysicsEasysingle choice

When a resistor of $11 Ω$ is connected in series with an electric cell in series, the current increases by $0 .4 A$ . The internal resistance of the cell is

Options:

Answer:

Solution:

$i = \frac{E}{R + r}$

$0.5 = \frac{E}{11 + r}$

$E = 5.5 + 0.5 r$

$0.9 = \frac{E}{5 + r}$

$E = 4.5 + 0.9 r$

On solving these equation, $r = 2.5 Ω$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Current ElectricitySubtopic:Battery

⏱ 2mℹ️ Source: PYQ_2020

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