Calculate the ratio of current flowing through the battery at t = 0 and t = ∞ . ( t = 0 is the time of closing of the switch)

At t = 0 capacitor is short circuit and inductor is open circuit. i 1 = 20 5 + 5 = 2 A At t = ∞ capacitor is open circuit and inductor is a short circuit. i 2 = 20 5 + 5 = 2 A ∴ i 1 i 2 = 2 2 = 1

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PhysicsCurrent ElectricityCircuit AnalysisEasy2 minPYQ_2020

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Calculate the ratio of current flowing through the battery at $t = 0$ and $t = \infty$ . ( $t = 0$ is the time of closing of the switch)

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Answer:

Solution:

At $t = 0$ capacitor is short circuit and inductor is open circuit.

$i_{1} = \frac{20}{5 + 5} = 2 A$

At $t = \infty$ capacitor is open circuit and inductor is a short circuit.

$i_{2} = \frac{20}{5 + 5} = 2 A$

$∴ \frac{i_{1}}{i_{2}} = \frac{2}{2} = 1$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Current ElectricitySubtopic:Circuit Analysis

⏱ 2mℹ️ Source: PYQ_2020

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