Physics - Current Electricity Question with Solution | TestHub

Initially balancing point is$\mathrm{J}$,

Hence$\frac{\mathrm{AJ}}{\mathrm{BJ}}=\frac{\mathrm{P}}{\mathrm{Q}}=\frac{20}{80}$

Now if$\mathrm{P}$&$\mathrm{Q}$are interchanged,

Let balancing point be${\mathrm{J}}_1$

$\frac{{\mathrm{AJ}}_1}{{\mathrm{BJ}}_1}=\frac{\mathrm{Q}}{\mathrm{P}}=\frac{80}{20}$

The balanced point shifts by${\mathrm{AJ}}_1-\mathrm{AJ}=80-20=60\mathrm{ }\mathrm{cm}$.