Physics - Current Electricity Question with Solution | TestHub

$-5{\mathrm{i}}_2-10\left({\mathrm{i}}_1+{\mathrm{i}}_2\right)-2{\mathrm{i}}_2+20=0$

$-10{\mathrm{i}}_1-17{\mathrm{i}}_2+20=0$

$-10+4{\mathrm{i}}_1+10\left({\mathrm{i}}_1+{\mathrm{i}}_2\right)=0$

$14{\mathrm{i}}_1+10{\mathrm{i}}_2+10=0$

$10{\mathrm{i}}_1+17{\mathrm{i}}_2=20\to \times 10$

$14{\mathrm{i}}_1+10{\mathrm{i}}_2=10\to 17$

$-138{\mathrm{i}}_1=30$

${\mathrm{i}}_1=-\frac{30}{138}=-0.217$

${\mathrm{i}}_1$ is negative it means current flows from positive to negative terminal