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Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityBatteryEasy2 minPYQ_2018

PhysicsEasysingle choice

Two batteries of emf $4 V$ and $8 V$ with internal resistance $1Ω$ and $2Ω$ are connected in a circuit with a resistance of $9Ω$ as shown in figure.
The current and potential difference between the points $P$ and $Q$ are

Options:

Answer:

Solution:

$I = \frac{8 - 4}{1 + 2 + 9} = \frac{4}{12} = \frac{1}{3} A V_{P} - V_{Q} = 4 - \frac{1}{3} \times 3 = 3 volt$

Stream:VITEEESubject:PhysicsTopic:Current ElectricitySubtopic:Battery

⏱ 2mℹ️ Source: PYQ_2018

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