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Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityElectrical instrumentEasy2 minPYQ_2014

PhysicsEasysingle choice

The resistance in the two arms of the meter bridge are $5 Ω$ and $R Ω,$ respectively. When the resistance $R$ is shunted with an equal resistance, the new balance point is at $1.6 l_{1} .$ The resistance ‘ $R$ ’ is:
NEET 2014

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Answer:

Solution:

The resistance of meter bridge is directly proportional to the length of the bridge wire.
$\frac{5}{R} = \frac{l_{1}}{100 - l_{1}}$
$\frac{5}{R / 2} = \frac{1.6 l_{1}}{100 - 1.6 l_{1}}$
Solving $l_{1} = 25 c m$ and $R = 15 Ω$

Stream:NEETSubject:PhysicsTopic:Current ElectricitySubtopic:Electrical instrument

⏱ 2mℹ️ Source: PYQ_2014

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