A galvanometer has current range of 15 mA and voltage range 750 mV . To convert this galvanometer into an ammeter of range 25 A , the required shunt is

Question

TestHub · Accepted Answer

Given: V = 750 × 1 0 − 3 V I g ​ = 15 × 1 0 − 3 A and I = 25 A Using, a = I g ​ y ​ = 15 × 1 0 − 3 750 × 1 0 − 3 ​ = 50Ω I g ​ = S + a S ​ × I 15 × 1 0 − 3 = ( S + 50 S ​ ) × 25 S = 0.03Ω ​

Physics - Current Electricity Question with Solution | TestHub

Options:

Doubts & Discussion