Four resistance of 10Ω , 60Ω , 100Ω and 200Ω respectively taken in order are used to form a Wheatstone's bridge. A 15 V battery is connected to the ends of a 200Ω resistance, the current through

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Four resistance of 10Ω , 60Ω , 100Ω and 200Ω respectively taken in order are used to form a Wheatstone's bridge. A 15 V battery is connected to the ends of a 200Ω resistance, the current through it will be

TestHub · Accepted Answer

Resistances 10Ω , 60Ω and 100Ω are in series and they together are in parallel to 200Ω resistance. When a potential difference of 15 V is applied across 200Ω then current through it I = 200 15 ​ = 7.5 × 1 0 − 2 A

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