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PhysicsCurrent ElectricityBatteryEasy2 minPYQ_2013

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The internal resistance of a $2.1 V$ cell which gives a current of $0.2 A$ through a resistance of $10Ω$ isNEET 2013 (All India)

Answer:

Solution:

$I = \frac{E}{R + r} 0.2 \times (10 + r) = 2.1 10 + r = \frac{2.1}{2} \times 10 r = 10.5 - 10 = 0.5Ω$

Stream:NEETSubject:PhysicsTopic:Current ElectricitySubtopic:Battery

⏱ 2mℹ️ Source: PYQ_2013

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