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Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityElectrical PowerHard2 minPYQ_2012

PhysicsHardsingle choice

An electric bulb marked as 50W-200V is connected across a $100 V$ supply. The present power of the bulb is

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Answer:

Solution:

We know that $R = \frac{V ^{2}}{P}$ Given $V = 200 V, P = 40 W$ and $V = 100 V$ Hence, $R = \frac{V ^{2}}{P} = \frac{200 \times 200}{50}$ $P = \frac{V ^{2}}{R} = \frac{100 \times 100 \times 50}{200 \times 200} P^{'} = 12.5 W$

Stream:WBJEESubject:PhysicsTopic:Current ElectricitySubtopic:Electrical Power

⏱ 2mℹ️ Source: PYQ_2012

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