Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityElectrical PowerEasy2 minPYQ_2011

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An electric bulb of $100 W$ is connected to a supply of electricity of $220 V$ . Resistance of the filament is

Answer:

Solution:

Power $P = \frac{V ^{2}}{R} = \frac{220 \times 220}{100} = 484 W$

Stream:VITEEESubject:PhysicsTopic:Current ElectricitySubtopic:Electrical Power

⏱ 2mℹ️ Source: PYQ_2011

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