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Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityEquivalent ResistanceMedium2 minPYQ_2009

PhysicsMediumsingle choice

A wire of resistance $5Ω$ is drawn out so that its new length is 3 times its original length. What is the reistance of the new wire?

Options:

Answer:

Solution:

$(\frac{r _{1}}{r _{2}})^{2} = (\frac{ℓ _{2}}{ℓ _{1}}) = \frac{3 ℓ}{ℓ} = 3$ $(\frac{R _{2}}{R _{1}}) = \frac{ℓ _{2}}{ℓ _{1}} \times \frac{A _{1}}{A _{2}} = 3 \times (\frac{r _{1}}{r _{2}})^{2} = 3 \times 3 \Rightarrow R_{2} = 45$

Stream:WBJEESubject:PhysicsTopic:Current ElectricitySubtopic:Equivalent Resistance

⏱ 2mℹ️ Source: PYQ_2009

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