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Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityElectrical instrumentMedium2 minPYQ_2008

PhysicsMediumsingle choice

A galvanometer of resistance $50Ω$ is connected to a battery of $3 V$ along with a resistance of $2950Ω$ in series. A full scale deflection of 30 divisions is obtained in the galvanometer. In order to reduce this deflection to 20 divisions, the resistance in series should beNEET 2008 (Mains)

Options:

Answer:

Solution:

$30 i_{0} = \frac{V}{R _{g} + 2950}; R_{g} = 50Ω 20 i_{0} = \frac{V}{R _{g} + R} \Rightarrow R = 4450Ω$

Stream:NEETSubject:PhysicsTopic:Current ElectricitySubtopic:Electrical instrument

⏱ 2mℹ️ Source: PYQ_2008

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